[Python笔记] locals() 函数
作用
locals()
函数会以字典类型返回当前位置的全部局部变量。对于函数, 方法, lambda
函式, 类, 以及实现了 __call__
方法的类实例, 它都返回 True
。
语法
In [27]: locals()返回值
返回字典类型的局部变量。
In [27]: locals() Out[27]: {'In': ['', u"get_ipython().magic(u'cls ')", u'def foo():\n c = 1\n def inner():\n x += 1\n return x\n return foo', u'print foo', u'print foo()()', u'def foo():\n c = 1\n def inner():\n c += 1\n return c\n return foo', u'def foo():\n c = 1\n def inner():\n c += 1\n return c\n return inner', u'def foo():\n c = 1\n def inner():\n c += 1\n return c\n return inner', u'print foo()()', u'print foo()', u'help()', u'c = 1', u'def foo():\n global c\n c = 1\n def inner():\n c += 1\n return c\n return inner', u'print foo()()', u'def foo():\n global c\n c = 1\n def inner():\n global c\n c += 1\n return c\n return inner', u'print foo()()', u'print locals()', u'def a():\n x =0\n def b():\n y = x +1 \n print locals()\n print x,y\n return b', .... In [30]: type(locals()) Out[30]: dict示例
In [31]: def foo(): ...: z = 1 ...: return locals() ...: In [32]: foo() Out[32]: {'z': 1}